23b^2+85b+26=-4-2b^2

Solution for 23b^2+85b+26=-4-2b^2 equation:

23b^2+85b+26=-4-2b^2

We move all terms to the left:

23b^2+85b+26-(-4-2b^2)=0

We get rid of parentheses

23b^2+2b^2+85b+4+26=0

We add all the numbers together, and all the variables

25b^2+85b+30=0

a = 25; b = 85; c = +30;
Δ = b2-4ac
Δ = 852-4·25·30
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-65}{2*25}=\frac{-150}{50}
=-3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+65}{2*25}=\frac{-20}{50}
=-2/5
$